1 select * from (select row_number() over() as num, xxx.* from xxx) as temp where num in (3567)
而我用
2 delete from (select * from (select row_number() over() as num, xxx.* from xxx) as temp where num in (1)
)
来删除的时候为什么不是我用1执行时候的数据
求大神帮忙
怎么来解决这样的情况
------解决方案--------------------------------------------------------
一个是1,一个是3567?
------解决方案--------------------------------------------------------