想做一个天气预报的功能,所以尝试着从网上的接口获取JSON数据,有一个在网上COPY下来的sycnhttp类,一个mainActivity,按照网上的教程先启动了tomcat,然后运行程序,结果出了问题,显示Toast为“未找到”,说明抛出了异常(经过我用Toast测试,在String retStr = syncHttp.httpGet(urlStr, paramsStr);这句时就无法执行了,但是可以进入try语句块,说明与后面对JSON的解析应该没什么关系。。应该就是这句话进行不下去,数据应该是没获取到),若水的教程把一个WAR包放到了tomcat的webapps文件夹中,我不会web开发什么的,小白不懂这个有用没?简单的从接口获取数据需要这个东西吗?这个天气接口,在浏览器上直接输入是有效的,但是在程序中无法获取到数据。小白求大神帮忙看看,到底是哪里出了问题呢??跪求大神啦,这任务比较紧

sycnhttp类
package com.leo.http;
import java.io.ByteArrayOutputStream;
import java.io.DataOutputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.List;
import org.apache.http.params.HttpConnectionParams;
import android.R.integer;
public class SyncHttp
{
private static final int TIME_OUT = 1000 * 6; // 超时
private static final String METHOD_POST = "POST";
private static final String METHOD_GET = "GET";
private static final int HTTP_OK = 200;
private final String CHARTSET = "UTF-8"; //字符编码
private final int BUFFER = 1024 * 8;//缓冲区
public String httpGet(String urlStr, String paramsStr) throws Exception
{
StringBuilder urlBuilder = new StringBuilder();
urlBuilder.append(urlStr);
if (null!=paramsStr&&!paramsStr.equals(""))
{
urlBuilder.append("?");
urlBuilder.append(paramsStr);
}
//Log.i(Constants.TAG, urlBuilder.toString());
URL url = null;
HttpURLConnection conn = null;
InputStream inStream = null;
String response = null;
try
{
url = new URL(urlBuilder.toString());
System.out.println("");
//根据URL打开远程连接
conn = (HttpURLConnection) url.openConnection();
//设置参数
conn.setDoInput(true);
conn.setConnectTimeout(TIME_OUT);
conn.setRequestMethod(METHOD_GET);
conn.setRequestProperty("accept", "*/*");
//建立连接
conn.connect();
//接受返回码
int responseCode = conn.getResponseCode();
if (responseCode == HTTP_OK)
{
//获取输入流
inStream = conn.getInputStream();
//从输入流中获取信息
response = getResponse(inStream);
}