字符串：aaa A.B(aafdsaaaaaaa);aaadcsafdsaaaaa c.B(aaaaadaaaa);aadfsa.D(aafdse);aaaaa A.B(aaaascaaaaa);aafdsaa
想替换“A.B(*);”里面的“);”部份，
我想要的思路是先获取到“A.B(aafdsaaaaaaa);”，再从这里面获取“);”,不知道这样二次获取的正则表达式怎么写
------解决方案--------------------------------------------------------
Like this?
- C# code
string tempStr = @"aaa A.B(aafdsaaaaaaa);aaadcsafdsaaaaa c.B(aaaaadaaaa);aadfsa.D(aafdse);aaaaa A.B(aaaascaaaaa);aafdsaa"; string replaceStr = "*"; tempStr = Regex.Replace(tempStr,@"(?<=\w+?\.\w+?\([^)]+?)\);",replaceStr); //aaa A.B(aafdsaaaaaaa*aaadcsafdsaaaaa c.B(aaaaadaaaa*aadfsa.D(aafdse*aaaaa A.B(aaaascaaaaa*aafdsaa
------解决方案--------------------------------------------------------
string a = "字符串：aaa A.B(aafdsaaaaaaa);aaadcsafdsaaaaa c.B(aaaaadaaaa);aadfsa.D(aafdse);aaaaa A.B(aaaascaaaaa);aafdsaa";
a = Regex.Replace(a,@"(?<=A.B\([^\(]*?)\)", "",RegexOptions.IgnoreCase);
//结果:
字符串：aaa A.B(aafdsaaaaaaa;aaadcsafdsaaaaa c.B(aaaaadaaaa);aadfsa.D(aafdse);aaaaa A.B(aaaascaaaaa;aafdsaa