有如下字符串可能值为
5
10ml
20ML
120ml*4
360+120ML
360+100ml
500ML+300ML
如何转换对应为
5
10
20
120
480
460
800
------解决方案--------------------------------------------------------
下面可以将每行的数组提取出来，不过你要处理一下运算符号，乘除加减，或者你改用其他方法
- C# code
StreamReader reader = new StreamReader("c:\\1.txt",Encoding.Default); while (!reader.EndOfStream) { int num = 0; string str = reader.ReadLine(); Regex reg = new Regex(@"(?is)\d+"); MatchCollection mc = reg.Matches(str); foreach (Match m in mc) { num += Convert.ToInt32(m.Value); } MessageBox.Show(num.ToString()); }
------解决方案--------------------------------------------------------
^\d+就可以了。
------解决方案--------------------------------------------------------
应该没什么简单的办法吧
- C# code
string text = @"5 10ml 20ML 120ml*4 360+120ML 360+100ml 500ML+300ML"; text = Regex.Replace(text, "[a-zA-Z]", ""); text = Regex.Replace(text, @"(?!\d+)(\*.*)", ""); var matches = Regex.Matches(text, @"(\d+)(\+(\d+))*"); foreach (Match match in matches) { if (match.Groups[2].Success) Console.WriteLine(Convert.ToInt32(match.Groups[1].Value) + Convert.ToInt32(match.Groups[3].Value)); else Console.WriteLine(Convert.ToInt32(match.Groups[1].Value)); }
------解决方案--------------------------------------------------------
- C# code
string[] source = { "5", "10ml", "20ML", "120ml*4", "360+120ML", "360+100ml", "500ML+300ML",};System.Text.RegularExpressions.Regex reg = new System.Text.RegularExpressions.Regex(@"([^\d\+\*])|(\*\d+)");System.Data.DataTable dt = new System.Data.DataTable();foreach (string s in source){ string result = dt.Compute(reg.Replace(s, string.Empty), null).ToString();}
------解决方案--------------------------------------------------------
- C# code
string[] strs ={ "5", "10ml", "20ML", "120ml*4", "360+120ML", "360+100ml", "500ML+300ML"}; foreach (string str in strs) { var filteredStr=Regex.Replace(str,@"[^\d+*?\d+]", ""); MatchCollection ms = new Regex(@"(?<!.+)\d+|(?<=\+)\d+").Matches(filteredStr); int num = 0; foreach (Match r in ms) { num += int.Parse(r.Value); }; Response.Write(num+"<br/>");