RT。
例如:有一段代码:
EMU0 : in bit; -- must be type in for compliance enable
-- non-JTAG type is inout
EMU1 : in bit; -- must be type in for compliance enable
-- non-JTAG type is inout
RSV0 : in bit;
怎样用正则把注释过滤掉,其他的输出。注释就是"--"符号后边的!
------解决方案--------------------------------------------------------
- C# code
string pattern = @"(?is)(?:--).*?(?:\n)"; string replacement = "\n"; string input = @"EMU0 : in bit; -- must be type in for compliance enable -- non-JTAG type is inout EMU1 : in bit; -- must be type in for compliance enable -- non-JTAG type is inout RSV0 : in bit;"; input = Regex.Replace(input, pattern, replacement); Console.WriteLine(input);/*EMU0 : in bit; EMU1 : in bit; RSV0 : in bit;*/
------解决方案--------------------------------------------------------
不考虑包在""中的--的话,这样就可以了
- C# code
string test = @"EMU0 : in bit; -- must be type in for compliance enable -- non-JTAG type is inout EMU1 : in bit; -- must be type in for compliance enable -- non-JTAG type is inout RSV0 : in bit;";Regex reg = new Regex(@"--.*");string result = reg.Replace(test, "");richTextBox2.Text = result;
------解决方案--------------------------------------------------------
单行注释是以换行为结束标志的,上述都是匹配行内的,不会换行匹配