<?xml version="1.0" encoding="utf-8" ?>
<Table>
<Row >
<Title>首页</Title>
<Name>企业首页</Name>
<Href>_self</Href>
<Url>index</Url>
<Mark>index</Mark>
</Row>
<Row >
<Title>产品展示</Title>
<Name>产品展示</Name>
<Href>_self</Href>
<Url>Pro</Url>
<Mark>Pro</Mark>
</Row>
</Table>
怎么通过 <Mark>的值返回父节点中的所有节点。也就是说，当我接收<Mark>值为index时，把
<Title>首页</Title>
<Name>企业首页</Name>
<Href>_self</Href>
<Url>index</Url>
<Mark>index</Mark>
以上内容返回到Dataset中
------解决方案--------------------------------------------------------
- C# code
string strXml = @"<Table> <Row > <Title>首页</Title> <Name>企业首页</Name> <Href>_self</Href> <Url>index</Url> <Mark>index</Mark> </Row> <Row > <Title>产品展示</Title> <Name>产品展示</Name> <Href>_self</Href> <Url>Pro</Url> <Mark>Pro</Mark> </Row> </Table>"; XmlDocument xdoc = new XmlDocument(); xdoc.LoadXml(strXml); string strXPath = "/Table/Row[Mark='index']"; XmlNodeList oXmlNodes = xdoc.SelectNodes(strXPath); //*************已经成取到所需的信息了*********** xdoc = new XmlDocument(); XmlDeclaration xmlDec = xdoc.CreateXmlDeclaration("1.0", "utf-8", null); XmlElement rootNode = xdoc.CreateElement("Table"); xdoc.InsertBefore(xmlDec, xdoc.DocumentElement); xdoc.AppendChild(rootNode); foreach (XmlNode node in oXmlNodes) { XmlElement xmlNew = xdoc.CreateElement("Row"); xmlNew.InnerXml = node.InnerXml; rootNode.AppendChild(xmlNew); } DataSet ds = new DataSet(); StringReader stream = new StringReader(xdoc.InnerXml); XmlTextReader reader = new XmlTextReader(stream); ds.ReadXml(reader);