怎么判断文本框输入的值只能是数字和回车建？ 大侠们 帮忙了！要有代码谢谢！
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前段时间写着玩的小东西，有你想要的东西
- HTML code
<html><head> <title>加减乘除</title> <script type="text/javascript"> window.onload = function () { var txtNumber1Emement = document.getElementById("txtNumber1"); var txtNumber2Emement = document.getElementById("txtNumber2"); var operatorTypeEmlement = document.getElementById("operatorType"); txtNumber1Emement.onkeydown = txtNumber2Emement.onkeydown = function (e) { e = e || window.event; var keyCode = e.keyCode || e.charCode; //清除键 if (keyCode == 8) { return; } //回车键 if (keyCode == 13) { doWork(); return; } //如果不是数字阻止输入 if (keyCode < 48 || keyCode > 57) { if (typeof e.preventDefault == "function") { e.preventDefault(); e.stopPropagation(); } else { e.returnValue = false; e.cancelBubble = true; } } } operatorTypeEmlement.onchange = function () { doWork(); } } function doWork() { var txtNumber1Value = document.getElementById("txtNumber1").value || 0; var txtNumber2Value = document.getElementById("txtNumber2").value || 0; var value1 = parseInt(txtNumber1Value, 10); var value2 = parseInt(txtNumber2Value, 10); var operator = document.getElementById("operatorType").value; document.getElementById("result").value = eval(value1 + operator + value2); } </script></head><body> <fieldset style="width: 600px; height: 500px; margin: 0px;"> <input type="text" id="txtNumber1" style="width: 270px; border-right-width: 0px; text-align: right" /><select id="operatorType" style="width: 163px; border-left-width: 0px"> <optgroup> <option value="+">+</option> <option value="-">-</option> <option value="*">*</option> <option value="/">/</option> </optgroup> </select><br /> <input type="text" id="txtNumber2" style="width: 270px" /><br /> = <input type="text" id="result" disabled="disabled" style="width: 100%" /> </fieldset></body></html>
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- JScript code
//输入数字function isNumber(txt,name){ var str=$(txt).value; var pattern =/^[0-9]*$/; if(str!="" && (!pattern.exec(str))) { alert(name+"请输入数字！"); return false; } else { return true; }}
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private void textBox1_KeyUp(object sender, KeyEventArgs e)
{
string key = this.textBox1.Text;
if (e.KeyCode == Keys.Enter)
{
Regex reg = new Regex(@"[\d]+");
if (reg.IsMatch(key))
{
MessageBox.Show("number");