读取XML某一节点下面的所有子节点的值解决思路_ASP.NET

读取XML某一节点下面的所有子节点的值
<display>
<website></website>
<siteurl></siteurl>
<city></city>
<category></category>
<dpshopid/>
<range/>
<address>
</address>
<major></major>
<title></title>
<image>
</image>
<startTime></startTime>
<endTime></endTime>
<value></value>
<price></price>
<rebate></rebate>
<bought></bought>
</display>
怎么得到display下面各个节点的值，C#

------解决方案--------------------------------------------------------

C# code

            string result = "";            XmlDocument xmldocument = new XmlDocument();            xmldocument.LoadXml(result);            XmlNodeList node = xmldocument.SelectNodes("//display");            foreach (XmlNode n in node)            {                string id = n.SelectSingleNode("website").InnerText;                string RName = n.SelectSingleNode("siteurl").InnerText;            }
------解决方案--------------------------------------------------------
 XmlNodeList node = xmldocument.SelectNodes("//display");

然后遍历node

------解决方案--------------------------------------------------------
探讨

 XmlNodeList node = xmldocument.SelectNodes("//display");

然后遍历node

------解决方案--------------------------------------------------------
XmlDocument doc=new XmlDocument();
doc.Load("");
 foreach (XmlNode node in doc.GetElementsByTagName(""))
 {
 foreach (XmlNode xn in node.ChildNodes)
 {
 Console.WriteLine(xn.InnerText);
 }
 }
或
XDocument Doc = XDocument.Load(@"");
var Query = from D in Doc.Elements("")
 select D;