现在的问题是：我希望能将文件上传到一台IP为10.101.10.1的服务器上，怎么写后台代码？
/// <summary>
/// 上传文件
/// </summary>
/// <param name="path">文件上传到的路径</param>
private void uploadFile(string path, out List<ElectronicAssistantModel> ElectronicAssistantList)
{
ElectronicAssistantList = new List<ElectronicAssistantModel>();
foreach (string upload in Request.Files)
{
if (!Request.Files[upload].HasFile()) continue;
if (!Directory.Exists(path))
{
Directory.CreateDirectory(path);
}
string filename = Path.GetFileName(Request.Files[upload].FileName);
Request.Files[upload].SaveAs(Path.Combine(path, filename));
ElectronicAssistantList.Add(new ElectronicAssistantModel
{
DocumentName = filename,
Url = path
});
}
}
这个上传到本服务器没有问题？但是这个 要上传到网络路径，怎么搞
网上有说在web.config里配置<identity impersonate="true" userName="test" password= "123456"/>
我没成功，期待高手帮忙！！！！
------解决方案--------------------------------------------------------
如果你是跨域上传 要嘛写webservice 要嘛在10.101.10.1弄个上传页面 然后用内框架链接到当前站点
第二种我没用过 不知道可行不可行
------解决方案--------------------------------------------------------
- C# code
namespace AppGet { public class PushCommand : CommandBase { protected override void Execute() { string uri = string.Format("http://{0}/App/Push/{1}", ConfigurationManager.AppSettings["AppCenter"], Args["-file"]); Console.WriteLine(uri); HttpWebRequest request = HttpWebRequest.Create(uri) as HttpWebRequest; request.Method = "POST"; using (Stream stream = request.GetRequestStream()) { var buffer = new byte[4096]; using (FileStream fs = new FileStream(Args["-file"], FileMode.Open)) { while (true) { int r = fs.Read(buffer, 0, 4096); if (r <= 0) { break; } stream.Write(buffer, 0, r); } } } request.GetResponse(); } private const string DefaultContentType = "application/octet"; }}
------解决方案--------------------------------------------------------
前面copy的是csharp client upload的代码
下面是mvc中接受文件的代码
- C# code
[AcceptVerbs(HttpVerbs.Post)] public void Push(string id) { string appName = id.Split('.')[0]; string targetFolder = Path.Combine(Server.MapPath("/Apps"), appName); if (!Directory.Exists(targetFolder)) { Directory.CreateDirectory(targetFolder); } var buffer = new byte[4096]; using (FileStream fs = new FileStream(Path.Combine(targetFolder, id), FileMode.Create)) { while (true) { int r = Request.InputStream.Read(buffer, 0, 4096); if (r <= 0) { break; } fs.Write(buffer, 0, r); } } }
------解决方案--------------------------------------------------------
mvc中上传文件
- C# code
[AcceptVerbs(HttpVerbs.Post)] public ContentResult Upload(HttpPostedFileBase FileData, string folder) { string result = ""; if (null != FileData) { try { if (PathHelper.CheckFileName(FileData.FileName) == false) throw new ApplicationException(); result = Path.GetFileName(FileData.FileName);//获得文件名 //string ext = Path.GetExtension(FileData.FileName);//获得文件扩展名 //string saveName = "uploadfile" + ext;//实际保存文件名 saveFile(FileData, folder, result);//保存文件 Logger.Instance.Info(this, "Upload", string.Format("上传文件{0}成功", result)); } catch (Exception ex) { result = ex.ToString(); Logger.Instance.Warn(this, "Upload", "上传文件失败，错误信息为：" + ex.ToString()); } } return Content(result); } [Authorize] [RoleFilter(checkRole = "1")] [NonAction] private void saveFile(HttpPostedFileBase postedFile, string filepath, string saveName) { filepath = filepath.Substring(6, filepath.Length - 6); if (!Directory.Exists(filepath)) { Directory.CreateDirectory(filepath); } try { postedFile.SaveAs(Path.Combine(filepath, saveName)); Logger.Instance.Info(this, "saveFile", string.Format("保存文件{0}成功", Path.Combine(filepath, saveName))); } catch (Exception e) { Logger.Instance.Warn(this, "saveFile", "保存文件失败，错误信息为：" + e.ToString()); throw new ApplicationException(e.Message); } }