如何这个程序会说小弟我的是32位的，在16位下不行？

;Title: Binary notation;---------------------------------------------------------------------------------------------;Description: Anohter implementation of complemental code edition using bit scan reverse method;Author: ;Finish date:2007-11-16;Modify date:;Algorithm:用一个数组保存16个二进制的ASCII码，初值全设为'0'。从前往后扫描，如里为全'0'则可以;          输出再退出程序，若非'0'刚记下［这是一个数字'1'所在的位置，将字符数组相应设为'1'，;          同时将扫描的二进制数的相应位设为0，再重新循环扫描。;----------------------------------------------------------------------------------------------.386data1   segment use16            ;Please   input   here   the   code   of   data   segment             val  dw  -28             msg  db  16 dup('0'),13,10,'$ ' data1   ends stack1   segment  use16        ;Please   input   here   the   code   of   data   segment stack1   ends code1   segment   use16        assume   cs:code1,ds:data1,ss:stack1 start:         mov     ax,data1         mov     ds,ax         ;Please   input   here   the   code   of   code   segment         mov     ax,[val]         mov     si,offset msg         add     si,15dscan:                                                 BSR     cx,ax                         ;Scan   the   binary,   get   the   subscript   of   bit   1         je      quit                          ;If   all   bits   are   0,   then   terminate   the   program         BTR     ax,cx                         ;set   the   bit   1   to   zero         sub     si,cx                         ;Get the offset of the digit 1         mov     byte ptr [si],'1'             ;set   '1 '   to   the   string         mov     si,offset msg         add     si,15d                        ;Reset address        jmp     scan quit:         mov     ah,9         mov     dx,offset   msg         int     21h         mov     ah,4ch         int     21h code1   ends         end     start