int[] jg = new int[] { 30, 31, 32, 33, 34, 35, 51, 52, 53, 60, 70, 70, 70, 70, 80, 100, 100, 100, 100, 150, 150, 150, 150, 150, 150};
例如:
jg[3] 到 jg[5]的值相加
33 34 35
怎么实现
------解决思路----------------------
int start = 3;
int end = 5;
int sum = jg.Skip(start).Take(end-start+1).Sum();