我个人认为难...我都郁闷了...
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sorting is not a problem --- the key is to break up the numbers.
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/*---------------------------------------------------------------------------
File name: 5=space.cpp
Author: HJin (email: fish_sea_bird [at] yahoo [dot] com )
Created on: 8/22/2007 12:57:23
Environment: Windows XP Professional SP2 English +
Visual Studio 2005 v8.0.50727.762
Modification history:
===========================================================================
Problem statement:
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http://bbs.bc-cn.net/viewthread.php?tid=164729
输入一行数字，如果我们把这行数字中的‘5’都看成空格，那么就得到一行用空格分割的若干非负整数（可能有些整数以‘0’开头，这些头部的‘0’应该被忽略掉，除非这个整数就是由若干个‘0’组成的，这时这个整数就是0）。然后对这些分隔的数排序,有小到大排.
Sample output:
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555123554758955555
555123554758955555
47 89 123
Press any key to continue . . .
12345678
12345678
678 1234
Press any key to continue . . .
0012350046700
0012350046700
123 46700
Press any key to continue . . .
*/
#include <iostream>
#include <string>
#include <vector>
#include <sstream>
#include <algorithm>
using namespace std;
int main()
{
string s;
int i;
vector<int> vi;
istringstream iss;
// get input
getline(cin, s);
cout<<s<<endl;
// replace '5' by ' '
for(i=0; i<s.size(); ++i)
{
if(s[i]=='5')
{
s[i]=' ';
}
}
// break up numbers
iss.str(s);
while(iss>>i)
{
vi.push_back(i);
}
// sort
sort(vi.begin(), vi.end());
// print
for(vector<int>::const_iterator it=vi.begin(); it!=vi.end(); ++it)
cout<<*it<<" ";
cout<<endl;
return 0;
}
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斑竹的代码果然厉害，不过int i; 应该改成 unsigned int i; 的吧，否则类型不匹配了。
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555123554758955555
555123554758955555
47 89 123
Press any key to continue . . .
12345678
12345678
678 1234
Press any key to continue . . .
0012350046700
0012350046700
123 46700
Press any key to continue . . .
这里怎么要输入两行才输出啊...而且我用vc运行输入两行相同的数字,他在输出一行与我输入一样的数字,然后才输出我想要的答案...这是什么原因????
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#include <iostream>
#include <string>
#include <vector>
#include <sstream>
#include <algorithm>
using namespace std;
int main()
{
string s;
int i;
vector<int> vi;
istringstream iss;
// get input
getline(cin, s); //让你输入一行数字，并存放在字符串s中
cout<<s<<endl; //在屏幕上输出字符串s
// replace '5' by ' '
for(i=0; i<s.size(); ++i)
{
if(s[i]=='5')
{
s[i]=' ';
}
}
// break up numbers
iss.str(s);
while(iss>>i)
{
vi.push_back(i);
}
// sort
sort(vi.begin(), vi.end());
// print
for(vector<int>::const_iterator it=vi.begin(); it!=vi.end(); ++it)
cout<<*it<<" ";
cout<<endl;
return 0;
}
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