[求助]编译没出错，运行出现2个error???

#include <stdio.h>
void inv(int*x,int n)
{
int *p,temp,*i,*j,m=(n-1)/2;
i=x;j=x+n-1;p=x+m;
for(;i<=p;i++,j--)
{temp=*i;*i=*j;*j=temp;}
return;
}
void mian()
{int i,a[10]={3,7,9,111,0,6,7,5,4,2};

printf("The original array:\n");

for(i=0;i<10;i++)

printf("%d,",a[i]);

printf("\n");

inv(a,10);

printf("The array has been inverted:\n");

for(i=0;i<10;i++)

printf("%d,",a[i]);

printf("\n");
}

----------------解决方案--------------------------------------------------------
这是谭浩强C语言的的原题，不过我用的编译器是VC++6.0，编译没有出错。运行是有2个erroe 大家看下是什么原因！谢谢
----------------解决方案--------------------------------------------------------
void mian()// main?
----------------解决方案--------------------------------------------------------
惭愧。。。错别字额。。。
----------------解决方案--------------------------------------------------------
void inv(int*x,int n) 既然是void,为什么还有return????


----------------解决方案--------------------------------------------------------

#include <stdio.h>
inv(int*x,int n)
{
int *p,temp,*i,*j,m=(n-1)/2;
i=x;j=x+n-1;p=x+m;
for(;i<=p;i++,j--)
{temp=*i;*i=*j;*j=temp;}
return;
}
void main()
{int i,a[10]={3,7,9,111,0,6,7,5,4,2};

printf("The original array:\n");

for(i=0;i<10;i++)

printf("%d,",a[i]);

printf("\n");

inv(a,10);

printf("The array has been inverted:\n");

for(i=0;i<10;i++)

printf("%d,",a[i]);

printf("\n");
}

改好了....

----------------解决方案--------------------------------------------------------

本来准备先写主函数的。..后来又.....

[此贴子已经被作者于2007-10-18 8:11:51编辑过]

----------------解决方案--------------------------------------------------------