帮忙瘦瘦身

这是个打任意空心长方形的程序,要求尽量简化,但是不能使用超出下边语句范围的语句,不能goto,只能whil/if
#include<stdio.h>
#include<windows.h>
int main()
{
    int x=0,y=0,i=1,j=1,k;
    printf("input chang (-1 to end):");
    scanf("%d",&x);   
    while(x!=-1){
       printf("input kuan :");
       scanf("%d",&y);
       while(i<=x){
             printf("*");
             ++i;}
       printf("\n");
       while(j<=y-2){
          printf("*");
          k=x-2;
          while(k!=0){
                      printf(" ");
                      k--;}
        printf("*");
        k=x-2;
        ++j;
        printf("\n");}
       i=1;j=1;
       while(i<=x){
             printf("*");
             ++i;}
       printf("\n");
       i=1;j=1;
       printf("input chang (-1 to end):");
       scanf("%d",&x);
       }  
    system("pause");
    return 0;}
----------------解决方案--------------------------------------------------------
#include "stdio.h"
main()
{
   int i,j,chang,kuan;
   printf("input chang :\n");
   scanf("%d",&chang);
   printf("input kuan :\n");
   scanf("%d",&kuan);
   for(i=0;i<=kuan;i++)
   {    for(j=0;j<=chang;j++)
        {   if((i>0&&i<kuan)&&(j>0&&j<chang))
                printf(" ");
            else      
               printf("*");
         }      
        printf("\n");
    }        
}

[[it] 本帖最后由 xianshizhe111 于 2008-3-13 22:22 编辑 [/it]]
----------------解决方案--------------------------------------------------------
#include "stdio.h"
main()
{
   int i=0,j=0,chang,kuan;
   printf("input chang :\n");
   scanf("%d",&chang);
   printf("input kuan :\n");
   scanf("%d",&kuan);
   while(i<=kuan)
   {   j=0;
       while(j<=chang)
       {   
            if((i>0&&i<kuan)&&(j>0&&j<chang))
                printf(" ");                 
            else      
               printf("*");
            j++;            
        }      
        printf("\n");
    i++;   
    }        
}
----------------解决方案--------------------------------------------------------
谢谢
----------------解决方案--------------------------------------------------------