大家帮我看一下哪儿错了,谢了

#include<stdio.h>
int print(int n);
void main()
{
    int i,n;
    printf("\nPlease enter 1 integer:");
    scanf("%d",&n);
    i=print(n);
    if(!i)printf("Error data!\n");
    printf("The value of print is %d!",i);
}
int print(int n)
{
    int i,j;
    if(n>=1&&n<=9)
    {
        for(i=1;i<=n;i++)
        {
            for(j=n-i;j>=1;j--)
                printf(" ");
            for(j=1;j<=2*i-1;j++)
                printf("%d",i);
            printf("\n");
        }
        return 1;
    }
    else
        return 0;
}

[[it] 本帖最后由 xu1988y 于 2008-4-17 01:25 编辑 [/it]]
----------------解决方案--------------------------------------------------------
#include<stdio.h>  //中间的空格呢?
int printf(int n);  // 你要重写printf函数阿? 应该是print吧!
void main()
{
    int i,n;
    printf("\nPlease enter 1 integer:");
    scanf("%d",&n);
    i=printf(n);   //这里
    if(!i)printf("Error data!\n");
    printf("The value of print is %d!",i);
}
int print(int n)
{
    int i,j;
    if(n>=1&&n<=9)
    {
        for(i=1;i<=n;i++)
        {
            for(j=n-i;j>=1;j--)
                printf(" ");
            for(j=1;j<=2*i-1;j++)
                printf("%d",i);
            printf("\n");
        }
        return 1;
    }
    else
        return 0;
}

[[it] 本帖最后由 mqh21364 于 2008-4-16 16:20 编辑 [/it]]
----------------解决方案--------------------------------------------------------
函数声明与调用处的函数名写错了.将printf改成print
----------------解决方案--------------------------------------------------------
谢了，我改下试试
----------------解决方案--------------------------------------------------------
谢了，看来大家都是高手啊，一眼就看出来了!!!
----------------解决方案--------------------------------------------------------