求正则表达式 ，提取出含有src属性中timeType文字的图片 并保存到数据库 同时将 生成的编号更新到alt 属性中
如：
<img title="" height="19" alt="0" width="36" score="0" src="../../ImportWord/images/timuType1.gif" />
<img title="" alt="0" width="212" height="19" score="0" src="../../ImportWord/images/timuType2.gif" />
<img src="abc.gif"/>
<img title="" alt="0" width="212" height="19" score="0" src="../../ImportWord/images/timuType2.gif" />
<img src="abc.gif"/>
<img title="" width="212" height="19" alt="0" score="0" src="../../ImportWord/images/timuType3.gif" />
图片的属性 摆放顺序不一样
结果输出：
<img title="" height="19" alt="1" width="36" score="0" src="../../ImportWord/images/timuType1.gif" />
<img title="" alt="2" width="212" height="19" score="0" src="../../ImportWord/images/timuType2.gif" />
<img title="" alt="3" width="212" height="19" score="0" src="../../ImportWord/images/timuType2.gif" />
<img title="" width="212" height="19" alt="4" score="0" src="../../ImportWord/images/timuType3.gif" />
这个正则表达式可以提取出图片 ,可是不知道怎么更新编号到alt属性中
Regex reg = new Regex(@"(?is)(<img(\s+title=""(?<title>[^""]*)""|\s+height=""(?<height>[^""]*)""|\s+alt=""(?<alt>[^""]*)""|\s+width=""(?<width>[^""]
*)""|\s+score=""(?<score>[^""]*)""|\s+src=""[^""]*timuType(?<type>\d+)\.gif"")+[ /]*>)");
------解决方案--------------------
提取和替换要分两步走..
提取后存入数据库后
你再替换:
string str = "<img .. alt=.. />";
str = Regex.Replace(str, @"(?i)(?<=alt="")[^""]*", "your编号");
------解决方案--------------------
你取匹配结果是用的循环吧，怎么会得不到自增编号？
------解决方案--------------------
- C# code
Regex reg = new Regex("..."); MatchCollection mc = reg.Matches(".........."); for (int i = 0; i < mc.Count; i++) { //取值 string value = mc[i].Value; string alt = mc[i].Groups["alt"].Value; //.... //替换为编号 value = Regex.Replace(value, @"(?i)(?<=alt="")[^""]*", i.ToString()); }
------解决方案--------------------
问一下，6楼的你能理解吗？？
把i.ToString() 改为 (i+1).ToString()