我做了一个简单的JAVA调用TOMCAT启动服务，界面用的SWT画的，点击启动服务菜单，TOMCAT正常启动，但是SWT界面就死掉了，请大家帮忙看一下，代码如下：
public class MainUI {
protected Shell shlDba = null;
Display display = Display.getDefault();
/**
* Launch the application.
*
* @param args
*/
public static void main(String[] args) {
try {
MainUI window = new MainUI();
window.open();
} catch (Exception e) {
e.printStackTrace();
}
}
/**
* Open the window.
*/
public void open() {
shlDba.open();
shlDba.layout();
while (!shlDba.isDisposed()) {
if (!display.readAndDispatch()) {
display.sleep();
}
}
shlDba.dispose();
display.dispose();
}
/**
*Close the window.
*/
public void close() {
if (!shlDba.isDisposed()) {
shlDba.close();
}
}
/**
* Create contents of the window.
*/
public MainUI() {
shlDba = new Shell();
shlDba.setSize(543, 602);
shlDba.setText("DBA自动化测试工具");
Menu menu = new Menu(shlDba, SWT.BAR);
shlDba.setMenuBar(menu);
MenuItem app = new MenuItem(menu, SWT.CASCADE);
app.setText("三层应用(APP)");
Menu menu_1 = new Menu(app);
app.setMenu(menu_1);
MenuItem start = new MenuItem(menu_1, SWT.NONE);
start.setText("启动服务");
start.addSelectionListener(new SelectionAdapter() {
public void widgetSelected(SelectionEvent e) {
// TODO Auto-generated method stub
try {
@SuppressWarnings("unused")
ServiceOperate start = new ServiceOperate(
"StartService.bat");
} catch (IOException e2) {
// TODO Auto-generated catch block
e2.printStackTrace();
}
}
});
MenuItem mntmq = new MenuItem(menu, SWT.NONE);
mntmq.setText("退出(Q)");
mntmq.addSelectionListener((new SelectionAdapter() {
public void widgetSelected(SelectionEvent e) {
System.exit(0);
}
}));
MenuItem stop = new MenuItem(menu_1, SWT.NONE);
stop.setText("停止服务");
stop.addSelectionListener(new SelectionAdapter() {
public void widgetSelected(SelectionEvent e) {
try {
@SuppressWarnings("unused")
ServiceOperate tt = new ServiceOperate("StopService.bat");
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
}
});
}
}
------解决方案--------------------
如果楼主你要是用非UI线程调用UI线程，SWT是不让的，你必须用UI线程调用，楼主可以试试，
我大概记得：
- Java code
Display.getDefault().asyncExec(new Runnable(){ public void run(){});//或者Display.getDefault().syncExec(new Runnable(){ public void run(){});
------解决方案--------------------
java使用 ProcessBuilder 的start 方法启动一个程序，返回一个 Process，调用这个 process的 destory 方法，程序就结束了。