GCD中的dispatch_apply的用法及作用
(一)dispatch_apply的基本用法
dispatch_apply函数是dispatch_sync函数和Dispatch Group的关联API,该函数按指定的次数将指定的Block追加到指定的Dispatch Queue中,并等到全部的处理执行结束
1 /*! 2 * @brief dispatch_apply的用法 3 */ 4 - (void)dispatchApplyTest1 { 5 //生成全局队列 6 dispatch_queue_t queue = dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0); 7 8 9 /*! dispatch_apply函数说明10 *11 * @brief dispatch_apply函数是dispatch_sync函数和Dispatch Group的关联API12 * 该函数按指定的次数将指定的Block追加到指定的Dispatch Queue中,并等到全部的处理执行结束13 *14 * @param 10 指定重复次数 指定10次15 * @param queue 追加对象的Dispatch Queue16 * @param index 带有参数的Block, index的作用是为了按执行的顺序区分各个Block17 *18 */19 dispatch_apply(10, queue, ^(size_t index) {20 NSLog(@"%zu", index);21 });22 NSLog(@"done");23 24 /*!25 * @brief 输出结果26 *27 2016-02-25 19:24:39.102 dispatch_apply测试[2985:165004] 028 2016-02-25 19:24:39.102 dispatch_apply测试[2985:165086] 129 2016-02-25 19:24:39.104 dispatch_apply测试[2985:165004] 430 2016-02-25 19:24:39.104 dispatch_apply测试[2985:165004] 531 2016-02-25 19:24:39.104 dispatch_apply测试[2985:165004] 632 2016-02-25 19:24:39.103 dispatch_apply测试[2985:165088] 333 2016-02-25 19:24:39.104 dispatch_apply测试[2985:165004] 734 2016-02-25 19:24:39.105 dispatch_apply测试[2985:165004] 835 2016-02-25 19:24:39.105 dispatch_apply测试[2985:165004] 936 2016-02-25 19:24:39.102 dispatch_apply测试[2985:165087] 237 2016-02-25 19:24:39.105 dispatch_apply测试[2985:165004] done38 * !!!因为在Global Dispatch Queue中执行,所以各个处理的执行时间不定39 但done一定会输出在最后的位置,因为dispatch_apply函数会等待所以的处理结束40 */41 }
(二)dispatch_apply的使用技巧:模拟for循环
1 /*! 2 * @brief 实例:当要对NSArray类对象的所有元素执行处理时,不必一个一个的编写for循环部分 3 */ 4 - (void)dispatchApplyTest2 { 5 //1.创建NSArray类对象 6 NSArray *array = @[@"a", @"b", @"c", @"d", @"e", @"f", @"g", @"h", @"i", @"j"]; 7 8 //2.创建一个全局队列 9 dispatch_queue_t queue = dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0);10 11 //3.通过dispatch_apply函数对NSArray中的全部元素进行处理,并等待处理完成,12 dispatch_apply([array count], queue, ^(size_t index) {13 NSLog(@"%zu: %@", index, [array objectAtIndex:index]);14 });15 NSLog(@"done");16 /*!17 * @brief 输出结果18 *19 2016-02-25 19:37:17.308 dispatch_apply测试[3010:167871] 0: a20 2016-02-25 19:37:17.308 dispatch_apply测试[3010:167956] 1: b21 2016-02-25 19:37:17.308 dispatch_apply测试[3010:167957] 3: d22 2016-02-25 19:37:17.308 dispatch_apply测试[3010:167871] 4: e23 2016-02-25 19:37:17.309 dispatch_apply测试[3010:167957] 6: g24 2016-02-25 19:37:17.309 dispatch_apply测试[3010:167871] 7: h25 2016-02-25 19:37:17.309 dispatch_apply测试[3010:167957] 8: i26 2016-02-25 19:37:17.309 dispatch_apply测试[3010:167871] 9: j27 2016-02-25 19:37:17.308 dispatch_apply测试[3010:167956] 5: f28 2016-02-25 19:37:17.308 dispatch_apply测试[3010:167955] 2: c29 * !!!因为在Global Dispatch Queue中执行,所以各个处理的执行时间不定30 但done一定会输出在最后的位置,因为dispatch_apply函数会等待所以的处理结束31 */32 }
(三)在dispatch_async函数中异步执行dispatch_apply函数,模拟dispatch_sync的同步效果
1 /*! 2 * @brief 推荐在dispatch_async函数中异步执行dispatch_apply函数 3 效果 dispatch_apply函数与dispatch_sync函数形同,会等待处理执行结束 4 */ 5 - (void)dispatchApplyTest3 { 6 NSArray *array = @[@"a", @"b", @"c", @"d", @"e", @"f", @"g", @"h", @"i", @"j"]; 7 dispatch_queue_t queue = dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0); 8 9 dispatch_async(queue, ^{10 11 dispatch_apply([array count], queue, ^(size_t index) {12 NSLog(@"%zu: %@", index, [array objectAtIndex:index]);13 });14 15 dispatch_async(dispatch_get_main_queue(), ^{16 NSLog(@"回到主线程执行用户界面更新等操作");17 });18 19 });20 /*!21 * @brief 执行结果22 *23 2016-02-25 19:49:53.189 dispatch_apply测试[3060:171856] 3: d24 2016-02-25 19:49:53.189 dispatch_apply测试[3060:171852] 1: b25 2016-02-25 19:49:53.189 dispatch_apply测试[3060:171853] 2: c26 2016-02-25 19:49:53.189 dispatch_apply测试[3060:171850] 0: a27 2016-02-25 19:49:53.189 dispatch_apply测试[3060:171856] 4: e28 2016-02-25 19:49:53.189 dispatch_apply测试[3060:171852] 5: f29 2016-02-25 19:49:53.190 dispatch_apply测试[3060:171853] 6: g30 2016-02-25 19:49:53.190 dispatch_apply测试[3060:171850] 7: h31 2016-02-25 19:49:53.190 dispatch_apply测试[3060:171852] 9: j32 2016-02-25 19:49:53.190 dispatch_apply测试[3060:171856] 8: i33 2016-02-25 19:49:53.218 dispatch_apply测试[3060:171760] 回到主线程执行用户界面更新等操作34 *35 */36 }