NSString *str=@"313233343536";//这是123456的ascii码
怎样把这一段字符串转换成123456呢
NSString *string = [NSString stringWithFormat:@"%c", asciiCode]; //
------解决方案--------------------
- (NSString *)TextFromAsciiCodesString:(NSString *)string
{
NSArray *components = [string componentsSeparatedByString:@" "];
NSUInteger len = [components count];
char new_str[len+1];
int i;
for (i = 0; i < len; ++i)
new_str[i] = [[components objectAtIndex:i] intValue];
new_str[i] = '\0';
return [NSString stringWithCString:new_str
encoding:NSASCIIStringEncoding];
}
转换后输出就是123456
------解决方案--------------------
- C/C++ code
NSString *str=@"495051525354"; const char* cstr = [str UTF8String]; printf("%s\n", cstr); char result[strlen(cstr) / 2 + 1]; int resultIdx = 0; for(int i=0; i<strlen(cstr); i+=2){ char* tmp = malloc(3); tmp[0] = cstr[i]; tmp[1] = cstr[i+1]; tmp[2] = '\0'; int a = atoi(tmp); //printf("%d\n", a); result[resultIdx++] = a; free(tmp); } result[strlen(cstr) / 2] = '\0'; printf("%s\n", result);
------解决方案--------------------
- C/C++ code
NSString *str=@"495051525354"; const char* cstr = [str UTF8String]; printf("%s\n", cstr); char result[strlen(cstr) / 2 + 1]; int resultIdx = 0; for(int i=0; i<strlen(cstr); i+=2){ char* tmp = malloc(3); tmp[0] = cstr[i]; tmp[1] = cstr[i+1]; tmp[2] = '\0'; int a = atoi(tmp); //printf("%d\n", a); result[resultIdx++] = a; free(tmp); } result[strlen(cstr) / 2] = '\0'; printf("%s\n", result);
------解决方案--------------------
楼主的ASCII码没错，是16进制的