{"A0":"2011-10-11 12:08:06:This is the first message","A1":"2011-10-11 12:08:06:This is the second message"}
我只要得到2011-10-11 12:08:06这样的时间和后面This is the first message消息就可以了，前面可能是A0到A1000。
最开始我想用splite按逗号分出A0和A1的消息内容后再通过“:”符分割出时间和消息，但发现时间里面有“:”符所以作罢。
请问大家有相应的解决经验么？
------解决方案--------------------
- Java code
public static void main(String[] args) { String testStr = "{\"A0\":\"2011-10-11 12:08:06:This is the first message\",\"A1\":\"2011-10-11 12:08:06:This is the second message\"}"; String reg = "\"A[\\d]+\":\"([\\d]{4}-[\\d]{2}-[\\d]{2} [\\d]{2}:[\\d]{2}:[\\d]{2}):([^\"]+)\""; Pattern p = Pattern.compile(reg); Matcher matcher = p.matcher(testStr); while (matcher.find()) { System.out.println(matcher.group(1) + " " + matcher.group(2)); } }