各位大侠帮小弟我解决这道超级简单的有关问题（冒泡排序的）_J2EE

各位大侠帮我解决这道超级简单的问题（冒泡排序的）
从控制端舒服一个字符串比如 4848adecb 然后排序后输出结果为4488abcde.

------解决方案--------------------
public static void main(String[] args) {
String values = "4848adecb";
char[] chars = new char[values.length()];
for (int i = 0; i < chars.length; i++) {
chars[i] = values.charAt(i);
}
Arrays.sort(chars);
String value = new String(chars);
System.out.println(value);
}
------解决方案--------------------

探讨

public static void main(String[] args) {
String values = "4848adecb";
char[] chars = new char[values.length()];
for (int i = 0; i < chars.length; i++) {
chars[i] = values.charAt(i);
}
Arrays.so……

------解决方案--------------------

Java code

public static String bubbleSort(String str){        char[] chars = new char[str.length()];        for(int i = 0 ; i < str.length() ; i++){            chars[i] = str.charAt(i);        }        for(int i = 0 ; i < chars.length ; i++){            for(int j = i + 1 ; j < chars.length ; j ++){                char temp;                if(chars[i] > chars[j]){                    temp = chars[i];                    chars[i] = chars[j];                    chars[j] = temp;                }            }        }        String retStr = "";        for(int i = 0 ; i < chars.length ; i ++){            retStr += chars[i];        }        return retStr;    }
------解决方案--------------------
LZ这个是完整版的
Java codepublic class BubbleSortTest {    public static String bubbleSort(String str){        char[] chars = new char[str.length()];        for(int i = 0 ; i < str.length() ; i++){            chars[i] = str.charAt(i);        }        for(int i = 0 ; i < chars.length ; i++){            for(int j = i + 1 ; j < chars.length ; j ++){                char temp;                if(chars[i] > chars[j]){                    temp = chars[i];                    chars[i] = chars[j];                    chars[j] = temp;                }            }        }        String retStr = "";        for(int i = 0 ; i < chars.length ; i ++){            retStr += chars[i];        }        return retStr;    }        public static void main(String[] args) {        System.out.println(bubbleSort(args.length > 0 ? args[0] : "kief351"));//如果控制端没有输入字符串就默认传一个    }}
------解决方案--------------------
探讨

LZ这个是完整版的
Java code
public class BubbleSortTest {

    public static String bubbleSort(String str){
        char[] chars = new char[str.length()];
        for(int i = 0 ; i < str.length() ; i++){
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