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struts2.18如何启动不了呢?Unable to load configuration. - action

热度:138   发布时间:2016-04-22 02:39:27.0
struts2.18怎么启动不了呢?Unable to load configuration. - action
tomcat6.0.14,struts2.1.81,简单的一个例子居然就不能成功,郁闷啊,已导入的jar包有7个,分别是:
commons-fileupload-1.2.1.jar
commons-io-1.3.2.jar
commons-logging-1.0.4.jar
freemarker-2.3.15.jar
ognl-2.7.3.jar
struts2-core-2.1.8.1.jar
xwork-core-2.1.6.jar

我的web.xml如下:
Java code
<?xml version="1.0" encoding="UTF-8"?><web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee   http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">    <filter>        <filter-name>struts2</filter-name>        <filter-class>            org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter        </filter-class>    </filter>    <filter-mapping>        <filter-name>struts2</filter-name>        <url-pattern>/*</url-pattern>    </filter-mapping>        <welcome-file-list>        <welcome-file>index.jsp</welcome-file>    </welcome-file-list>    </web-app>


src下的struts.xml如下:
Java code
<?xml version="1.0" encoding="UTF-8" ?><!DOCTYPE struts PUBLIC    "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"    "http://struts.apache.org/dtds/struts-2.0.dtd"><struts>    <package name="reg" extends="struts-default">        <action name="register" class="com.ac.action.RegisterAction" >            <result type="success">/succ.jsp</result>            <result type="failure">/fail.jsp</result>        </action>    </package></struts>


RegisterAction.java如下:
Java code
package com.ac.action;import com.opensymphony.xwork2.ActionSupport;public class RegisterAction extends ActionSupport {    private String username;    private String password;    private String password2;        public String getUsername() {        return username;    }    public void setUsername(String username) {        this.username = username;    }    public String getPassword() {        return password;    }    public void setPassword(String password) {        this.password = password;    }    public String getPassword2() {        return password2;    }    public void setPassword2(String password2) {        this.password2 = password2;    }        @Override    public String execute() throws Exception {        return "success";            }}


conf下的sever.xml如下:
Java code
..<Context path="/reg" docBase="E:\workspace\aaa\WebRoot" reloadable="true"> </Context>..


reg.jsp如下:
Java code
  <body>    <form action="register.action" method="post">      <table border="0">        <tr>          <td>用户名:</td>          <td><input type="text" name="username" /></td>        </tr>        <tr>          <td>密    码:</td>          <td><input type="password" name="password" /></td>        </tr>        <tr>          <td>重复密码:</td>          <td><input type="password" name="password2" /></td>        </tr>        <tr>          <td colspan="2" align="center"><input type="submit" value="注册"   /></td>        </tr>      </table>    </form>  </body>
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