update A
set a = "12"
where car = "car1"
这条sql语句用我想用hibernate执行，该如何操作？我用的是hibernate3.
我试图这样写：
- Java code
try { session = HibernateSessionFactory.getSession(); tx = session.beginTransaction(); String hql = "update Maccount set maccount.weekcount = 12 where maccount.id = 1"; Query query = session.createSQLQuery(hql).addEntity("maccount", Maccount.class).addJoin("id", "maccount.id").addJoin( "weekcount", "maccount.weekcount"); tx.commit(); } catch (Exception e) { e.printStackTrace(); if (tx != null) { tx.rollback(); tx = null; } } finally { if (session != null) { session.close(); session = null; } }虽然不报错，但执行出来没有效果。请问各路高僧，这是何原因？
------解决方案--------------------
tx = session.beginTransaction();
String hql = "update Maccount set weekcount = 12 where id = 1";
Query query = session.createQuery(hql);
query.executeUpdate();
tx.commit();