算数题,该怎么处理_J2EE

算数题
用A，B ，C 来表示一个三进制的书，例如A十进制的0，以此类推A=0，B=1，C=2。BA=3，BC=5，BAAA=27最大位6位数，
也就是CCCCCC，用java完成此运算。

------解决方案--------------------

Java code

        String s = Integer.toString(728, 3);        byte[] bytes = s.getBytes();        for(int i = 0; i < bytes.length; i++){            System.out.println(bytes[i]);            bytes[i] = (byte)(bytes[i] + 17);        }        System.out.println(new String(bytes));
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for example
Java codepublic class csdn {    public static void main(String[] args) throws Throwable {        String s = "222222";        System.out.println(Integer.parseInt(s, 3));        System.out.println(toString(728, 3));    }    public static String toString(int n, int radix) {        char[] dig = {'A', 'B', 'C'};        if (radix > dig.length) {return "100000";}        String s = Integer.toString(n, radix);        StringBuilder buf = new StringBuilder();        for (char c : s.toCharArray()) {            buf.append(dig[c-'0']);        }        return buf.toString();    }}
------解决方案--------------------
 String s = Integer.toString(728, 3);
       byte[] bytes = s.getBytes();
       for(int i = 0; i < bytes.length; i++){
           System.out.println(bytes[i]);
           bytes[i] = (byte)(bytes[i] + 17);
       }
       System.out.println(new String(bytes));

------解决方案--------------------
[code=Java][/code]
System.out.println("输入要处理的数字（最大值728）：");
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		String s = br.readLine();
		Integer co = Integer.parseInt(s);
		if(co <= 728){
			String ss = Integer.toString(co, 3);
			byte[] by = ss.getBytes();
			for(int i=0; i<by.length; i++){
				by[i] = (byte)(by[i] + ('A' - '0'));
			}
			System.out.println(new String(by));
		}else
			System.out.println("请输入不大于728的数！");
------解决方案--------------------
Java codeSystem.out.println("输入要处理的数字（最大值728）：");        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));        String s = br.readLine();        Integer co = Integer.parseInt(s);        if(co <= 728){            String ss = Integer.toString(co, 3);            byte[] by = ss.getBytes();            for(int i=0; i<by.length; i++){                by[i] = (byte)(by[i] + ('A' - '0'));            }            System.out.println(new String(by));        }else            System.out.println("请输入不大于728的数！");