String str[]={"asd","1sdf","sfe","asd","ddd","sss","ddd","sss","wer","erw"};也就是如何将这个数组中的不同值取出来并保存。这个str的长度并不确定。每取出一个值先判断是否相同，相同的放在一起，不同的有多少个则创建多少个数组保存。
------解决方案--------------------------------------------------------
总觉得这需求好怪。。。。
打印结果：
[1sdf]
[asd, asd]
[ddd, ddd]
[erw]
[sfe]
[sss, sss]
[wer]
- Java code
public static void main(String[] args) { String str[] = { "asd", "1sdf", "sfe", "asd", "ddd", "sss", "ddd", "sss", "wer", "erw" }; Set<String> set = new HashSet<String>(); Map<String, Integer> map = new TreeMap<String, Integer>(); for (String s : str) { if (set.add(s)) { map.put(s, 1); } else { map.put(s, map.get(s) + 1); } } int size = map.size(); int i = 0; String[][] result = new String[size][]; for (String key : map.keySet()) { if (map.get(key) == 1) { result[i] = new String[] { key }; } else { result[i] = new String[map.get(key)]; for (int j = 0; j < map.get(key); j++) { result[i][j] = key; } } i++; } for (String[] s : result) { System.out.println(Arrays.toString(s)); } }