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那位大神帮小弟我看看这题,要判断字符在字符串中出现的次数

热度:5642   发布时间:2013-02-25 00:00:00.0
那位大神帮我看看这题,要判断字符在字符串中出现的次数!
import java.util.Scanner;

public class Counter
{
public int counter(String inputs, String word)
{
int counter = 0;
int index = 0;
for (int i = 0; i < inputs.length() - 1; i++)
{
if (inputs.indexOf(word) == 0)
{
counter++;
index++;
}
}
return counter;
}

public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
Counter find = new Counter();
System.out.print("请输入一个字符串:");
String inputs = input.next();
System.out.print("请输入要查找的字符:");
String word = input.next();
int num = find.counter(inputs, word);
System.out.println(inputs + "中包含" + num + "个" + word);
}
}
我输出的结果是字符的下标,而不是次数,那位大神帮我修改一下~谢谢!

------解决方案--------------------------------------------------------
Java code
import java.util.Scanner;public class Counter {    public int counter(String inputs, String word) {        int counter = 0;        int index =0;        for (int i = 0; i <= inputs.length() - 1; i++) {            if ( ( index = inputs.indexOf(word) ) !=-1 ) {                counter++;                inputs = inputs.substring(index+word.length());            }        }        return counter;    }    public static void main(String[] args) {        Scanner input = new Scanner(System.in);        Counter find = new Counter();        System.out.print("请输入一个字符串:");        String inputs = input.next();        System.out.print("请输入要查找的字符:");        String word = input.next();        int num = find.counter(inputs, word);        System.out.println(inputs + "中包含" + num + "个" + word);    }}
------解决方案--------------------------------------------------------
Java code
import java.util.Scanner;public class Counter {    public int counter(String inputs, String word) {        int counter = 0;        int index =0;//        //        for (int i = 0; i < inputs.length() - 1; i++) { //要用 <=//            if (inputs.indexOf(word) == 0) {  //要换成!=-1  !=-1意为找到一次,让count++才有意义//                counter++;//                index++;  //仔细看看你的index,哪都没用到,这是毛用...//            }//        }//        return counter;                for (int i = 0; i <= inputs.length() - 1; i++) {            if ( ( index = inputs.indexOf(word) ) !=-1 ) {                                //上句代码意思为若inputs="abcdefgabckabcii"                //                          word="abc";                //则每找到一次abc就,让inputs=从c后的那个d开始形成的子串即为defgabckabcii;                //然后再循环往覆,直到结束.                                //而上面的for(循环其实意思不大),最好直接用//            while(( index = inputs.indexOf(word) ) !=-1 ){//                counter++;//                inputs = inputs.substring(index+word.length());//            }                            }        }        return counter;    }    public static void main(String[] args) {        Scanner input = new Scanner(System.in);        Counter find = new Counter();        System.out.print("请输入一个字符串:");        String inputs = input.next();        System.out.print("请输入要查找的字符:");        String word = input.next();        int num = find.counter(inputs, word);        System.out.println(inputs + "中包含" + num + "个" + word);    }}
------解决方案--------------------------------------------------------
Java code
String str = "aafcfasfqefdsasfaff";                  //e表示需要匹配的数据,使用Pattern建立匹配模式          Pattern p = Pattern.compile("as");                  //使用Matcher进行各种查找替换操作          Matcher m = p.matcher(str);          int i = 0;          while(m.find()){              i++;          }                    System.out.println(i);
------解决方案--------------------------------------------------------
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