递归的兑现过程咋写_J2SE

递归的实现过程咋写?
比如计算从1到200用递归计算怎么写?

int result = 0;

public static void main(String[] args) {

test t = new test();
System.out.println(t.digui(1));

}

public int digui(int number) {
result = result + number;
number++;
while (number <= 200) {
digui(number);
System.out.println(result);
}
return result;
}

咋一直死循环?

------解决方案--------------------

Java code

public class Test07 {    int result = 0;    public void digui(int number) {        if (number > 200) {            return;        }        result += number;        digui(number + 1);    }    public static void main(String[] args) {        Test07 t = new Test07();        t.digui(0);        System.out.println(t.result);    }}
------解决方案--------------------
lz改成：
int result = 0;

public static void main(String[] args) {

test t = new test();
System.out.println(t.digui(1));

}

public int digui(int number) {
result = result + number;
number++;
if (number <= 200) {
digui(number);
System.out.println(result);
}
return result;
}

就不会死循环了


------解决方案--------------------
从1到200什么？求和还是阶乘还是。。。
问题都没描述清楚

Java codepublic static void main(String[] args) {    test t = new test();    System.out.println(t.digui(200));}public int digui(int number) { //递归求和    if (number <= 1) return number;    return number + digui(number-1);}
------解决方案--------------------
参考下:

Java code    int digui(int n)    {        if(n==0)        {            return n;        }        else        {            return n+digui(n-1);        }    }
------解决方案--------------------
                Java codenumber++;        while (number <= 5) {            digui(number);            System.out.println(result);        }
------解决方案--------------------
这是我帮你改过的
[code=Java][/code]
public class Test1{
	int result = 0;
	public static void main(String[] args) {
   Test1 t = new Test1();
   t.digui(1);
}

public void digui(int number) {
result = result + number;
number++;
if (number <= 20) {
digui(number);
}else
System.out.println(result);
}

}

------解决方案--------------------
Java codepublic class Test {    public static void main(String[] args) {        Test t = new Test();        System.out.println(t.digui(200));    }    public int digui(int number) {        if(number == 1){            return 1;        }else{            return number + digui(number - 1);        }    }}