1,1,2,3,5,8,13
这样斐波那契数列的简单循环公式如何建立?怎么也想不出来了
------解决方案--------------------
- Java code
public static unsigned int fib(int n){ unsigned int fn=0,f0=1,f1=1; for(int i = 1;i < n;i++){ fn = f0 + f1; f0 = f1; f1 = fn; } return fn;}
public static unsigned int fib(int n){ unsigned int fn=0,f0=1,f1=1; for(int i = 1;i < n;i++){ fn = f0 + f1; f0 = f1; f1 = fn; } return fn;}