遍历一个HashMap,要求时间复杂度尽可能小。
------解决方案--------------------
Map map = new HashMap();
Iterator iter = map.entrySet().iterator();
while (iter.hasNext()) {
Map.Entry entry = (Map.Entry) iter.next();
Object key = entry.getKey();
Object val = entry.getValue();
}
------解决方案--------------------
效率高
- Java code
Map map = new HashMap();Iterator iter = map.entrySet().iterator();while (iter.hasNext()) { Map.Entry entry = (Map.Entry) iter.next(); Object key = entry.getKey(); Object val = entry.getValue();}