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Junit怎么对静态代码块进行测试

热度:132   发布时间:2016-04-24 01:44:28.0
Junit如何对静态代码块进行测试
有一个静态代码块如下:
Java code
public class JdbcUtil {    private final static String databaseUrl = "jdbc:mysql://localhost:3306/";    private final static String databaseName = "jdbc";    private final static String databaseUser = "root";    private final static String databasePwd = "root";    private final static String driverName = "com.mysql.jdbc.Driver";    private final static String driverRegex = "/^[A-Za-z](/.)[A-Za-z](/.)[A-Za-z](/.)[A-Za-z]$/";        static {        try {            Pattern p = Pattern.compile(driverRegex);            Matcher m = p.matcher(driverName);            System.out.println("是否匹配" + m.matches());            Class.forName(driverName);        } catch (ClassNotFoundException e) {            // TODO Auto-generated catch block            e.printStackTrace();        }    }}


要对static 中的内容进行测试,在JUNIT中应该如何操作?
急。在线等高手指教。

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百度一下,你就知道
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