关于方法的返回值解决办法_J2SE

关于方法的返回值
程序如下

class TestStuff
{
public int takeTwo(int x, int y)
{
//x = 0; y = 3;
int z = x > y ? x : y;
return z;
//System.out.println("Max is " + z);
}

public static void main(String[] args)
{

TestStuff t = new TestStuff();
t.takeTwo(12,3);
}
}

以上能运行，但没有值，当保留"System.out.println("Max is " + z);"这句时，提示此句是不可运行代码
我要怎样才行将Z的值显示出来呢？

------解决方案--------------------

Java code

class TestStuff{public int takeTwo(int x, int y){//x = 0; y = 3;int z = x > y ? x : y;return z;//System.out.println("Max is " + z);}public static void main(String[] args){TestStuff t = new TestStuff();System.out.println(t.takeTwo(12,3));}}
------解决方案--------------------
public int takeTwo(int x, int y)
{
//x = 0; y = 3;
int z = x > y ? x : y;
return z;
//System.out.println("Max is " + z);
}

System.out.println("Max is " + z); 这句话必须放到return前面去！！