大家好：
如何用正则按需求处理以下字符串呢！
将
@article{AcharyaBI93,
author = "Acharya, A. and Badrinath, B.R. and Imielinski, T.",
title = "Impact of Mobility on Distributed Computations",
journal = OSR,
volume = 27,
number = 2,
pages = "15-20",
month = "April",
year = 1993
}
找出“article”和“=”前所有关键字，并把引号变成花括号，关键字变为大写，最后结果为：
@Article{AcharyaBI93,
AUTHOR = {Acharya, A. and Badrinath, B. R. and Imielinski, T.},
TITLE = {Impact of Mobility on Distributed Computations},
JOURNAL = {Operating Systems Review},
VOLUME = 27,
NUMBER = 2,
PAGES = {15--20},
MONTH = {April},
YEAR = 1993
}
谢谢各位，不胜感激
------解决方案--------------------
话说
Acharya, A. and Badrinath, B. R. and Imielinski, T. --> Acharya, A. and Badrinath, B.R. and Imielinski, T.
OSR --> Operating Systems Review
15-20 --> 15--20
是怎么回事
------解决方案--------------------
忘了key变大写了
- Java code
//String separator = System.getProperty("line.separator"); String separator = "\n"; //不知道LZ是否按行分割的， //如果不是按行分割，用separator=""，也能对应，就是结果只有1行String s = "@article{AcharyaBI93," + "\n" +"author = \"Acharya, A. and Badrinath, B.R. and Imielinski, T.\"," + separator + "title = \"Impact of Mobility on Distributed Computations\"," + separator +"journal = OSR," + separator +"volume = 27," + separator +"number = 2," + separator +"pages = \"15-20\"," + separator +"month = \"April\"," + separator +"year = 1993" + separator +"}";System.out.println("----------original----------");System.out.println(s);s = s.replaceAll("^@article(.*)", "@Article$1").replaceAll("\"(.*?)\"", "{$1}");StringBuffer buf = new StringBuffer();Pattern p = Pattern.compile("((?<=("+separator+"[}],|,|))[^,]*?)(\\s*=\\s*.*?("+separator+"|[}],|,))");Matcher m = p.matcher(s);while (m.find()) { String s1 = m.group(1); System.out.println(m.group(1)); m.appendReplacement(buf, m.group(1).toUpperCase()+"$3");}m.appendTail(buf);System.out.println("----------after replace----------");System.out.println(buf);