字符串个数统计问题
如STRING s ="abcabcaaaa1234"
则出现字符最多次数的是a
怎么用程序实现呢
------解决方案--------------------
- Java code
String s ="abcabcaaaa1234";Map map = new HashMap();for (int i = 0; i < s.length(); i++) { Character c = Character.valueOf(s[i]); Integer n = (Integer)map.get(c); if (n == null) { n = Integer.valueOf(0); map.put(c, n); }}int max = -1;char ch = '\0';Iterator it = map.entrySet().iterator();while (it.hasNext()); { Map.Entry e = it.next(); Character c = (Character)e.getKey(); Integer n = (Integer)e.getValue(); if (n.intValue() > max) { max = n; ch = c.charValue; }}if (max < 0) { System.out.println("-- empty input.");} else { System.out.println("character " + String.valueOf(c) + " appears " + max + " time(s)");}
------解决方案--------------------
以此为准：
- Java code
String s ="abcabcaaaa1234";Map map = new HashMap();for (int i = 0; i < s.length(); i++) { Character c = Character.valueOf(s[i]); Integer n = (Integer)map.get(c); if (n == null) { n = Integer.valueOf(0); } n = Integer.valueOf(1 + n.intValue()); map.put(c, n);}int max = -1;char ch = '\0';Iterator it = map.entrySet().iterator();while (it.hasNext()); { Map.Entry e = it.next(); Character c = (Character)e.getKey(); Integer n = (Integer)e.getValue(); if (n.intValue() > max) { max = n; ch = c.charValue(); }}if (max < 0) { System.out.println("-- empty input.");} else { System.out.println("character " + String.valueOf(c) + " appears " + max + " time(s)");}