哪位高手能帮我写一个java的小数循环程序 然我研究一下
如将2.5循环为2.555555555
谢谢了 在线等
------解决方案--------------------
public static void a(float i, int count) {
String ss = "";
String str = String.valueOf(i);
String[] s = new String[2];
int index = str.indexOf(".");
String a1 = "";
String a2 = "";
if(index>=0){
a1 = str.substring(0,index+1);
a2 = str.substring(index+1);
}
for(int j =0;j<count;j++){
a1 += a2;
}System.out.println(a1);
/* s = str.split(".");
for (int j = 0; j < count; j++) {
ss += s[0];
}
System.out.println(ss);*/
}
------解决方案--------------------
long getFmum(float input, int innum)
{
float result = input;
int num = innum;
float snum = (result - (int)result);
int length = getLong(snum);
while(num > 0)
{
result += snum*1e-(num*length);
num--;
}
return result;
}
int getLong(float input)
{
int result;
while(1)
{ if( input*10 != 0 )
{
input = input* 10 - (int)(input* 10)
result++;
}else{ break; }
}
return result;
}
------解决方案--------------------
- Java code
public class test4 { /** * @param args */ private static double getdouble(double s,int c) { // TODO Auto-generated method stub String str = String.valueOf(s); int count = str.indexOf("."); if(count!=-1){ StringBuffer a = new StringBuffer(str.substring(0,count+1)); String b = str.substring(count+1); for(int i = 0 ; i < c;i++){ a.append(b); } s = Double.valueOf(a.toString()).doubleValue(); } return s; } public static void main(String[] args) { double s = 32.534; s = getdouble(s,3); System.out.println(s); }}