字符串格式如下，但每列的长度不一定一致，用“,”或者“,空格”隔开。
V,20120202,235900,59651,P,00998, 0, 4, 6.3408, 6.1846, 0.1562,19675, 9.08124,Km, 0.142276,PPP
V,20120202,240000,59651,P,00998, 0, 4, 6.3438, 6.193, 0.1505,19675, 20.97290,Km, 0.143011,PPP
请问如何分别提取20120202 235900 和 9.09124
------解决方案--------------------
- Java code
String str = "V,20120202,235900,59651,P,00998, 0, 4, 6.3408, 6.1846, 0.1562,19675, 9.08124,Km, 0.142276,PPP"; Pattern p = Pattern.compile("[^,]+,\\s*([^,]+),\\s*([^,]+)(,[^,]+){9},\\s*([^,]+).*"); Matcher m = p.matcher(str); if(m.matches()) { System.out.println(m.group(1)); System.out.println(m.group(2)); System.out.println(m.group(4)); }