hibernate查询结果现实问题_Java Web开发

hibernate查询结果现实问题

程序代码：

    public static void main(String[] args) {
        UinfoDAO dao = new UinfoDAO();
        Object obj = (Object)"wx";
        try{
           Uinfo uinfo = new Uinfo();
           uinfo.setUname("wx");
           Collection list = dao.findByUname(obj);
           Iterator iter = list.iterator();
           while (iter.hasNext()) {
               System.out.println("Sign is :" + iter.next().toString());
           }
        }catch(HibernateException e){
            System.out.println("Entity retrieval failed.");
            e.printStackTrace();
        }finally{
            try{
                dao.getSession().close();
            }catch(Exception e){
                //do nothing;
            }
        }


    }
}

结果为Sign is :com.genuitec.hibernate.Uinfo@1a3e41f
是查询方法不对，还是哪里不对啊？请大家帮帮忙

搜索更多相关主题的帖子: hibernate 现实 obj iter 结果

----------------解决方案--------------------------------------------------------
输写出错了
把iter.next()赋给一个实体
在输出实体的属性
----------------解决方案--------------------------------------------------------
public static void main(String[] args) {
        UinfoDAO dao = new UinfoDAO();
        Object obj = (Object)"wx";
        try{
           Uinfo uinfo = new Uinfo();
           uinfo.setUname("wx");
           Collection list = dao.findByUname(obj);
           Iterator iter = list.iterator();
           while (iter.hasNext()) {
//问题在这里  iter.next()它获得的结果是一个对象,对象输出来的是该对象的一个地址
//             Uinfo uinfo = (Uinfo)iter.next();
//             System.out.println(uinfo.getUname());
               System.out.println("Sign is :" + iter.next().toString());
           }
        }catch(HibernateException e){
            System.out.println("Entity retrieval failed.");
            e.printStackTrace();
        }finally{
            try{
                dao.getSession().close();
            }catch(Exception e){
                //do nothing;
            }
        }


    }
}
----------------解决方案--------------------------------------------------------