求一个简单的算法，急，先谢了
输入一个参数，燃火打印出相应的维数，例：输入4 输出0000
0111
0122
0123
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算法
----------------解决方案--------------------------------------------------------
程序代码：
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
while(n<=0){
System.out.println("n must greater than zero, please input a number again");
n = in.nextInt();
}
int a[][] = new int[n][n];
for(int i = 0; i<n;i++){
for(int j=0;j<n;j++){
if(j>=i)
a[i][j]=i;
else
a[i][j]=j;
System.out.print(a[i][j]+" ");
}
System.out.println();
}
}
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
while(n<=0){
System.out.println("n must greater than zero, please input a number again");
n = in.nextInt();
}
int a[][] = new int[n][n];
for(int i = 0; i<n;i++){
for(int j=0;j<n;j++){
if(j>=i)
a[i][j]=i;
else
a[i][j]=j;
System.out.print(a[i][j]+" ");
}
System.out.println();
}
}
}
----------------解决方案--------------------------------------------------------
for(int i=0;i<4;i++)
{
for(int j=0;j<4;j++)
System.out.print(j>i?i:j);
System.out.println();
}
这个是不是更精辟一些呢
----------------解决方案--------------------------------------------------------