（急）jsp下传压缩文件并到服务器端能自动解压_Java Web开发

（急）jsp上传压缩文件并到服务器端能自动解压
上传压缩文件我可以实现了，就是不知道怎么让压缩文件在指定的目录（即文件上传到的目录）下解压，请大家帮忙！
有代码最好了，呵呵，在线等。。。。

------解决方案--------------------------------------------------------
1 你会解压缩吗？
2 既然会，那么把上传的文件保存成文件，然后解开不就行了！

------解决方案--------------------------------------------------------
java.unil.zip.ZipFile
解压
------解决方案--------------------------------------------------------

Java code

import java.io.File;import java.io.FileInputStream;import java.io.FileOutputStream;import java.util.zip.ZipEntry;import java.util.zip.ZipInputStream;import java.util.zip.ZipOutputStream;public class TestZip {    public void zip(String zipFileName, String inputFile) throws Exception {        zip(zipFileName, new File(inputFile));    }    public void zip(String zipFileName, File inputFile) throws Exception {        ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFileName));        zip(out, inputFile, "");        System.out.println("zip done");        out.close();    }    public void unzip(String zipFileName, String outputDirectory)            throws Exception {        ZipInputStream in = new ZipInputStream(new FileInputStream(zipFileName));        ZipEntry z;        while ((z = in.getNextEntry()) != null) {            System.out.println("unziping " + z.getName());            if (z.isDirectory()) {                String name = z.getName();                name = name.substring(0, name.length() - 1);                File f = new File(outputDirectory + File.separator + name);                f.mkdir();                System.out.println("mkdir " + outputDirectory + File.separator                        + name);            } else {                File f = new File(outputDirectory + File.separator                        + z.getName());                f.createNewFile();                FileOutputStream out = new FileOutputStream(f);                int b;                while ((b = in.read()) != -1)                    out.write(b);                out.close();            }        }        in.close();    }    public void zip(ZipOutputStream out, File f, String base) throws Exception {        System.out.println("Zipping  " + f.getName());        if (f.isDirectory()) {            File[] fl = f.listFiles();            out.putNextEntry(new ZipEntry(base + "/"));            base = base.length() == 0 ? "" : base + "/";            for (int i = 0; i < fl.length; i++) {                zip(out, fl[i], base + fl[i].getName());            }        } else {            out.putNextEntry(new ZipEntry(base));            FileInputStream in = new FileInputStream(f);            int b;            while ((b = in.read()) != -1)                out.write(b);            in.close();        }    }    public static void main(String[] args) {        try {            TestZip t = new TestZip();            t.zip("D:/zip.zip", "D:/zip");            t.unzip("D:/zip.zip", "D:/newZip");        } catch (Exception e) {            e.printStackTrace(System.out);        }    }}
------解决方案--------------------------------------------------------
import java.io.File;  
import java.io.FileInputStream;  
import java.io.FileOutputStream;  
import java.util.ArrayList;  
import java.util.zip.ZipEntry;  
import java.util.zip.ZipInputStream;  

public class ZipToFile {


	public static boolean zipToFile(String sZipPathFile, String sDestPath) {  
       boolean flag = false;  
       try {  
    
           FileInputStream fins = new FileInputStream(sZipPathFile);  
    
           ZipInputStream zins = new ZipInputStream(fins);  
           ZipEntry ze = null;  
           byte ch[] = new byte[256];  
           while ((ze = zins.getNextEntry()) != null) {