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为什么小弟我的js没有运行

热度:6927   发布时间:2013-02-25 21:16:33.0
为什么我的js没有运行
这个代码有点长,不过都很容易懂,我是初学者,麻烦帮我看看为什么我的js没有运行起来
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
  <base href="<%=basePath%>">
   
  <title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">  
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
<script language = "javascript" type = "text/javascript" src = "jquery-1.7.2.js"/></script>
<script language = "javascript" type = "text/javascript" src = "ajax.js"/></script>
<script language = "javascript" type = "text/javascript" src = "username.js"/></script>
  </head>
  
  <body>
  <center>
  <h3>测试ajax</h3>
  <form action="#" method = "post">
  <table>
   
  <tr>
  <td>用户名:</td>
  <td><input type = "text" name = "username" id = "user_name"onchange="javascript:checkname()"></td>
  <td><div id = "point_out"></div></td>
  </tr>
   
  <tr>
  <td>密码:</td>
  <td><input type = "password" name = "password" id = "user_password" onchange="javascript:password()"></td>
  <td><div id = "point_out2"></div></td>
  </tr>
   
  <tr>
  <td>再次输入密码:</td>
  <td><input type = "password" name = "password2" id = "user_password2" onchange="javascript:checkright()"></td>
  <td><div id = "point_out3"></div></td>
  </tr>
   
  </table>
  </form>
  </center>
  </body>
</html>
js文件是这样的

function checkname(){
var username = document.getElementById("user_name").value;
var ajax = creatAjax();
var url = "/servlet/deal?p"+username;
ajax.open("GET",url,"true");
ajax.send();
ajax.onreadystatechange=function()
{
  if (readyState==4 && ajax.status==200)
  {
  var res = ajax.responseText;
  var con = "";
  if(res == 1){
  con = "恭喜,该用户名可以注册";
  }else{
  con = "对不起,请换其他用户名";
  }
  document.getElementById("point_out").innerHTML=con;
  }
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