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AJAX 传递数据如何样才可以是 json

热度:1742   发布时间:2013-02-25 21:16:42.0
AJAX 传递数据怎么样才可以是 json

JScript code
var http_request = false;   function makeRequest(url,value) {       http_request = false;       if (window.XMLHttpRequest) {           http_request = new XMLHttpRequest();           if (http_request.overrideMimeType) {               http_request.overrideMimeType('text/xml');           }       }       else if (window.ActiveXObject) { // IE           try {               http_request = new ActiveXObject("Msxml2.XMLHTTP");           } catch (e) {               try {                   http_request = new ActiveXObject("Microsoft.XMLHTTP");               } catch (e) { }           }       }       if (!http_request) {           alert('Giving up :( Cannot create an XMLHTTP instance');           return false;       }       http_request.onreadystatechange = alertContents;       //    http_request.open('GET', url, true);       //    http_request.send(null);       //http_request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");           http_request.open('POST', url, true);      var data= value.toLocaleString();//转换还是失败       http_request.send(data); //这里的值是json的格式,现在只支持字符串啊这怎么写啊?         }   function alertContents() {       if (http_request.readyState == 4) {           if (http_request.status == 200) {               var text = http_request.responseText;               var myresult = http_request.responseXML;               var count = myresult.childNodes[1].childNodes[0].text;               if (count == 1) {                   alert('成功');               } else {                   alert('失败' + http_request.responseXML);               }           }           else {               alert('连接出现问题');           }       }   }


------解决方案--------------------------------------------------------
var text = http_request.responseText;
var jsonObj = eval('(' + text + ')');
var name = jsonObj.name
------解决方案--------------------------------------------------------
传递对象的时候可以用json,{user1:{name:张三,age:30},user2:{name:李四,age:40}}
------解决方案--------------------------------------------------------
传递的data以这种形式:
var data={key1:value1,key2:value2,key3:value3,...}
 http_request.send(data);
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