如何判断时间安排范围是否包含

import java.text.SimpleDateFormat;import java.util.Date;import java.util.HashMap;import java.util.Map;public class Test {    @SuppressWarnings({ "rawtypes", "unchecked" })    public static void main(String[] args) throws Exception{        Map examtimemap = new HashMap<String, String>();        examtimemap.put("starttime1","2012-07-02 08:00");        examtimemap.put("endtime1","2012-07-02 09:00");        examtimemap.put("starttime2","2012-07-02 08:40");        examtimemap.put("endtime2","2012-07-02 10:00");        examtimemap.put("starttime3","2012-07-02 09:05");        examtimemap.put("endtime3","2012-07-02 09:45");        examtimemap.put("starttime4","2012-07-02 10:00");        examtimemap.put("endtime4","2012-07-02 11:00");        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm");        for(int i = 1 ; i < 4;i++){            Date endtimei = sdf.parse(examtimemap.get("endtime" + i).toString());            for(int j = i + 1;j < 5;j++){                Date startTimej = sdf.parse(examtimemap.get("starttime" + j).toString());                if(endtimei.compareTo(startTimej) > 0){                    System.out.println("时间" + j + "与时间" + i + "有冲突");                    break;                }            }                    }    }}
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伪代码

Java code
首先创建一个class(TestTime)里面存放这几个成员。String className;//科目名称Date startTime;//开始时间Date endTime;//结束时间声明一个List集合:List<TestTime> list = new ArrayList(TestTime)();然后有几门课程就去创建几个TestTime对象，并实例化，然后添加到List集合中。再然后就遍历这个List集合:for(int i = 0; i < list.size(); i++){    for(int j = i+1; j < list.size(); j++){        //这里将遍历的对象list.get(i)的endTtime和list.get(j)的startTime比较一下就OK了。    }}
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Java code
public static boolean isDate( Date[] date , Date[] dates){                if(date[0].getTime()>dates[0].getTime()){            if(date[0].getTime()<dates[1].getTime()){                return false;            }        }        if(date[0].getTime()<dates[0].getTime()){            if(date[1].getTime()>dates[0].getTime()){                return false;            }        }        if(date[0].getTime()==dates[0].getTime()){                return false;        }        return true ;    }      public static void main(String[] args) throws ParseException {        Map<String, String[]> examtimemap = new LinkedHashMap<String, String[]>();//有序的Map        examtimemap.put("date",new String []{"2012-07-02 08:00","2012-07-02 08:00"});        examtimemap.put("date2",new String []{"2012-07-02 08:40","2012-07-02 10:00"});        examtimemap.put("date3",new String []{"2012-07-02 09:05","2012-07-02 09:45"});        examtimemap.put("date4",new String []{"2012-07-02 10:00","2012-07-02 11:00"});        SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm") ;        int i = 0, i2=0 ; ;        for (String key : examtimemap.keySet()) {                    for (String key2 : examtimemap.keySet()){                if(i2>i){                                    String [] dates =    examtimemap.get(key) ;                String [] dates2 =    examtimemap.get(key2) ;                Date[]  date = {dateFormat.parse(dates[0]) ,dateFormat.parse(dates[1])} ;                Date[]  date2 = {dateFormat.parse(dates2[0]) ,dateFormat.parse(dates2[1])} ;             if(!isDate( date , date2)){                 System.out.println(key +"和"+key2 + "时间有冲突");             }                }                i2= i2+1 ;            }            i=i+1 ;            i2 = 0;        }             }