IUserDao
- Java code
public interface IUserDao { public User queryByUserNameAndPassword(String userName, String password) throws Exception;}
UserDao
- Java code
public User queryByUserNameAndPassword(String userName, String password) throws Exception { String hql = "FROM User as u WHERE u.userName=? and u.password=?"; String[] str = new String[] {userName, password}; List<User> users = this.getHibernateTemplate().find(hql, str); if (users != null && users.size() >= 1) { return users.get(1); } else { return null; } }
IUserService
- Java code
public String isLogin(String userName, String password) throws Exception;
userService
- Java code
public String isLogin(String userName, String password) throws Exception { User user = userDao.queryByUserNameAndPassword(userName, password); if(user != null) { return user.getUserName(); } else { return null; } }
UserAction
- Java code
public String execute() throws Exception { if (isInvalid(user.getUserName())) { this.addFieldError("uid", "登录ID不能为空"); return INPUT; } if (isInvalid(user.getPassword())) { this.addFieldError("password", "密码项不能为空"); return INPUT; } String uname = userService.isLogin(user.getUserName(), user.getPassword()); if (uname != null) { Map session = ActionContext.getContext().getSession(); session.put("uname", uname); session.put("uid", user.getUid()); return SUCCESS; } else { this.addFieldError("idorpassword", "用户名或密码错误"); return INPUT; } } private boolean isInvalid(String userName) { // TODO Auto-generated method stub return false; }
不够写了 在下面
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初始化action有错误,也就是说你的action对应累的函数处理有问题,你好好查查
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<action name="login" class="userAction">
<bean id="userAction" class="com.action.UserAction">
<property name="userService" ref="userService"></property>
</bean>
不能这样注入action的吧
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<constant name="struts.objectFactory.spring.autoWire" value="name" />
定义一下这个常量, 让spring自动按名字注入service
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美女,sessionFactory配置错误。
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
</bean>
把这个加上
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