例如，字符串“25482”，
如果按1组来分需要得到如下结果：
x25482
如果按2组来分得到如下结果：
x2548x2,
x254x82,
x25x482,
x2x5482
如果按3组来分需要得到如下结果：
x254x8x2,
x25x4x82,
x25x48x2,
x2x5x482,
x2x45,x82,
x2x548x2
不能乱序。
------解决方案--------------------------------------------------------
for example
- Java code
import java.util.*;public class Test { public static void main(String[] args) throws Throwable { String s = "25482"; for (int i=0; i<s.length(); i++) { System.out.printf("-------- %d div test --------\n", i+1); for (List<String> l : div(s, i+1)) { System.out.println(l); } } } public static List<List<String>> div(String src, int count) { List<List<String>> result = new ArrayList<List<String>>(); if (src==null || src.length()==0 || count < 1 || count > src.length()) { return result; } if (count == 1) { List<String> list = new ArrayList<String>(); list.add(src); result.add(list); return result; } for (int i=0; i<src.length(); i++) { String s = src.substring(0, i+1); if (i+1 < src.length()) { List<List<String>> t = div(src.substring(i+1), count-1); for (List<String> l : t) { l.add(0, s); result.add(l); } } } return result; }}
------解决方案--------------------------------------------------------
- C# code
using System;using System.Collections.Generic;using System.Linq;using System.Text;namespace ConsoleApplication1{ class Program { static void Main(string[] args) { string s = "25482"; int n = 2; var data = Enumerable.Range(1, s.Length - 1); IEnumerable<int[]> query = data.Select(x => new int[] { x }); for (int i = 1; i < n; i++) { query = query.SelectMany(x => data.Select(y => x.Concat(new int[] { y }).ToArray())); } query = query .Select(x => x.OrderBy(y => y).Distinct().ToArray()) .Where(x => x.Count() == n - 1) .OrderByDescending(x => string.Join(",", x)) .GroupBy(x => string.Join(",", x)) .Select(x => x.First()) .Select(x => new int[] { 0 }.Concat(x).ToArray()); foreach (var item in query) { Console.WriteLine(string.Join("", s.Select((x, i) => item.Contains(i) ? "x" + x : x.ToString()))); } } }}