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struts2+jquery+ajax 回调函数没反应啊请们帮忙看看啊 跪谢

热度:6331   发布时间:2013-02-25 21:19:24.0
struts2+jquery+ajax 回调函数没反应啊,请大虾们帮忙看看啊 跪谢!
Action代码:
Java code
package com.ktv.action;import java.util.ArrayList;import java.util.HashMap;import java.util.List;import java.util.Map;import SongServiceImpl.SongServiceImpl;import com.ktv.common.action.KtvAction;import com.ktv.entity.Song;import com.ktv.service.SongService;public class SongAction extends KtvAction {    private SongService songservice;    private List<Song> songs = new ArrayList<Song>();        public SongAction(){        songservice = new SongServiceImpl();    }        public String songList(){        String songname = super.getParameter("songname");        songs = songservice.getSongsBySingeralias(songname);        System.out.println(songname);        System.out.println(songs.get(0).getName());        return "songlist";    }        //getter and setter    public List<Song> getSongs() {        return songs;    }    public void setSongs(List<Song> songs) {        this.songs = songs;    }    }


js代码:
JScript code
$(function(){        $("#btn1").click(function(){        var songname = $("#songnameform").val();        var data = {"songname":songname}        var url = "/ktv/song/song!songList.action";        $.post(url,data,function(json){            var songlist = json.songs;            alert(songlist);        },"json");    });        });


XML代码:
XML code
<?xml version="1.0" encoding="UTF-8" ?><!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd"><struts>    <package name="song" namespace="/song" extends="json-default">        <action name="song" class="com.ktv.action.SongAction">            <result name="songlist" type="json"/>        </action>    </package></struts>    


------解决方案--------------------------------------------------------
你进action方法了吗
------解决方案--------------------------------------------------------
地址栏直接输入 /ktv/song/song!songList.action 你的ajax请求,看看有没有json返回
------解决方案--------------------------------------------------------
你把双引号改成单引号试下

------解决方案--------------------------------------------------------
JSONArray js =JSONArray.fromObject(songs);
out.write(js.toString()); 貌似你该申请个输出流输出一下吧 前台才能得到 在后台方法中写
------解决方案--------------------------------------------------------
返回结果有封装json格式的数据吗?
JSONObject json=new JSONObject();
json.put("status", 0);
json.put("songname", songname);
Java code
public String songList(){        String songname = super.getParameter("songname");        songs = songservice.getSongsBySingeralias(songname);        System.out.println(songname);        System.out.println(songs.get(0).getName());        return "songlist";    }
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