问题描述
我在使用Java询问Direct Whole名称时遇到问题。
System.out.println("DOCTOR");
System.out.println("Enter ID Number:");
idnumber = scan.next();
System.out.println("Enter Name");
name = scan.next();
System.out.println("Enter Field of Specialization:");
field = scan.next();
System.out.println("ID               " + idnumber);
System.out.println("Name             " + name);
System.out.println("Specializtion    " + field );
当我在下面输入以下信息时:
ID = 100姓名= Brandon Sullano
它给了我这个结果
ID               100    
Name             Brandon    
Specializtion    Sullano
 
     我希望Name是动态的,所以我甚至可以输入两个单词怎么做? 
 
     提前致谢.. 
1楼
采用:
name = scan.nextLine();
 
     此外,如果ID号是一个整数,使用nextInt() (确保也将idnumber声明为int而不是string ) 
固定代码:
System.out.println("DOCTOR");
System.out.println("Enter ID Number:");
idnumber = scan.nextInt();
scan.nextLine();
System.out.println("Enter Name");
name = scan.nextLine();
System.out.println("Enter Field of Specialization:");
field = scan.nextLine();
System.out.println("ID               " + idnumber);
System.out.println("Name             " + name);
System.out.println("Specializtion    " + field );
使用
next()将在空格之前获取所有输入。nextLine()将在按下return之前获取所有输入。
 
     更多关于Scanner  
 
     专业提示:在大多数情况下,您将使用scan.nextLine()而不是scan.next()因此您可能希望养成使用它的习惯。 
2楼
试试这段代码:
import java.util.Scanner;
public class DoctorDoctor {
    public static void main (String [] args) {
        int idnumber;
        String name, field;
        Scanner sc = new Scanner(System.in);
        System.out.println("DOCTOR");
        /** Assuming ID number is an integer value */
        System.out.print("Enter ID Number: ");
        idnumber = sc.nextInt();
        sc.nextLine(); // This is important, for clearing the new line character
        System.out.print("Enter Name: ");
        name = sc.nextLine();
        System.out.print("Enter Field of Specialization: ");
        field = sc.nextLine();
        System.out.println();
        System.out.printf("%-15s: %d%n", "ID Number", idnumber);
        System.out.printf("%-15s: %s%n", "Name", name);
        System.out.printf("%-15s: %s%n", "Specialization", field);
        sc.close();
    }
}
输入/输出示例:
DOCTOR
Enter ID Number: 100
Enter Name: Brandon
Enter Field of Specialization: Heart Surgeon
ID Number      : 100
Name           : Brandon
Specialization : Heart Surgeon
3楼
 
     既然你说scan.nextLine() “不起作用”,我建议使用BufferedReader 。 
BufferedReader br=new BufferedReader(new InputStreamReader(System.in);
//in your code:
int idnumber = Integer.parseInt(br.readLine());
String name = br.readLine();
String field = br.readLine(); 
 
     您必须导入java.io.BufferedReader和java.io.InputStreamReader