$(".list-type").css("display")=="none" ?$(".list-type").css("display","block"):$(".list-type").css("display","none");
$(".type-shop-list").css("display")=="none" ?$(".type-shop-list").css("display","block"):$(".type-shop-list").css("display","none");
如果显示的就隐藏,如果隐藏的就显示
------解决方案--------------------
$(".list-type").toggle()
------解决方案--------------------
$(".list-type,.type-shop-list").toggle();