jquery的Ajax返回值如何取 _JavaScript

jquery的Ajax返回值怎么取？


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

    <title></title>

    <script src="jquery-1.8.0.min.js" type="text/javascript"></script>

    <script type="text/javascript">

        var test = {

            getValue: function (key) {

                if (key == '1') {

                    return 'A';

                } else {

                    return 'B';

                }

            },

            getAjaxValue: function (key) {

                $.ajax({

                    type: "post", async: false, cache: false, dataType: "text",

                    url: '../../Handler/JavaScriptSession.ashx',

                    data: [

                    { name: "action", value: "read" },

                    { name: "name", value: key },

                    { name: "value", value: "" }

                    ],

                    success: function (result) {

                        if (result != "error" || result != "true") {

                            alert("内部"+result);//这值能得到，并成功alert出

                            return "返回值"+result;

                        }

                    },

                    error: function () {