1: $("input[typename=Adetail]").each(function (i) {
listA.push($(this).val());
})
2: $.ajax({
type: "POST",
url: "../../../Handler/TravelRequestFamilyHandler.ashx",
data: { maininfo: main.join("#"), detailAinfo: detailA.join("#"), detailBinfo: detailB.join("#"), detailCinfo: detailC.join("#"), typeinfo: $("#hiddenVal").val(), savetype: $("#hiddenSaveType").val(), tcrtype: objtype },
async: false,
success: function (textStatus) {
if (textStatus = "success") {
$("#hiddenWebA").val(detailA.join("#"));
$("#hiddenWebB").val(detailB.join("#"));
$("#hiddenWebC").val(detailC.join("#"));
}
else {
alertinfo = "error";
}
},
error: function () {
alertinfo = "error";
}
});
return alertinfo;
3: setTimeout(function () { objbtn.disabled = "disabled"; }, 1);
document.getElementById('divProcessing').style.display = 'block';
4: if (confirm(confirmtext)) {
if (objtype == "3") {
var mail = $("#txtEmail").val(); ;
var companyMail = $("#hdEmail").val();
if (companyMail != "") {
mail += ";" + companyMail;
}
mail += ";yinxiaorong@petrochina-hfy.com;wangzhongfei@petrochina-hfy.com;liuxiaodan@petrochina-hfy.com;liuying@petrochina-hfy.com;";
var dateDeadLine = $("#txtGSDate").val();
var userName = $("#ddlPassportNameTitle option:selected").text() + " " + $("#txtPassportName").val();
var url = "mailto:liwendi.metco@gmail.com;ivy.metco@gmail.com?cc=" + mail + "&body=Dear Agency,%0A Enclosed please find the finalized TR, and issue the ticket for " + userName + " no later than " + dateDeadLine + ".%0A Regards%0A Travel%0ATel: 00971 50 1819 894%0AExt: 29188%0Atravel@petrochina-hfy.com";
window.open(url, "", "", "");
}
额,为题有点多
------解决方案--------------------
问题是你想问什么呢
------解决方案--------------------
我弱弱的问一句,LZ你想问啥呢?
------解决方案--------------------
LZ需要学习jquery的基础知识
------解决方案--------------------
------解决方案--------------------
1: $("input[typename=Adetail]").each(function (i) {
listA.push($(this).val());
})
修正为:将所有typename属性的值为Adetail的input进行遍历,并将它们的值增加到数组listA中
打多了两字“的值”