问题描述
我有以下字符串...
{
"Qualifications[0].DegreeType": "Degree Type 1",
"Qualifications[0].Classification": "Clasification 1",
"Qualifications[0].CourseTitle": "Course Title 1",
"Qualifications[0].YearOfAward": "2018",
"Qualifications[0].AwardingInstitution": "Awarding institution 1",
"Qualifications[1].DegreeType": "Degree Type 2",
"Qualifications[1].Classification": "Classification 2",
"Qualifications[1].CourseTitle": "Course Title 2",
"Qualifications[1].YearOfAward": "2019",
"Qualifications[1].AwardingInstitution": "Awarding Institution 2",
... and so on...
}
有谁知道将其转换为javascript对象的简单方法,这样我就可以有效地...
$(Qualifications).each(i, v){
//do stuff on whatever property of Qualifications[i]
}
我能想到的唯一方法是使用字符串操作以及类似下面的内容,但是它需要针对每个属性进行大量自定义代码检查映射,而我正在寻找更通用,更简单的方法。
let i = 0;
while (Qualifications[" + i +"].whateverProperty..) {
//add to object array
i++;
}
1楼
您可以通过移动给定对象来拆分键并减少路径。
如果不存在任何对象,请使用名称或数组创建一个新属性。 稍后分配值。
function setValue(object, path, value) { var way = path.replace(/\\[/g, '.').replace(/\\]/g, '').split('.'), last = way.pop(); way.reduce(function (o, k, i, kk) { return o[k] = o[k] || (isFinite(i + 1 in kk ? kk[i + 1] : last) ? [] : {}); }, object)[last] = value; } var object = { "Qualifications[0].DegreeType": "Degree Type 1", "Qualifications[0].Classification": "Clasification 1", "Qualifications[0].CourseTitle": "Course Title 1", "Qualifications[0].YearOfAward": "2018", "Qualifications[0].AwardingInstitution": "Awarding institution 1", "Qualifications[1].DegreeType": "Degree Type 2", "Qualifications[1].Classification": "Classification 2", "Qualifications[1].CourseTitle": "Course Title 2", "Qualifications[1].YearOfAward": "2019", "Qualifications[1].AwardingInstitution": "Awarding Institution 2" }, result = {}; Object.entries(object).forEach(([k, v]) => setValue(result, k, v)); console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
2楼
您可以像这样简单地使用标准的Object.keys
:
let qualifications = []
const my_object = {
"Qualifications[0].DegreeType": "Degree Type 1",
"Qualifications[0].Classification": "Clasification 1",
"Qualifications[0].CourseTitle": "Course Title 1",
...
}
Object.keys(my_object).forEach(key => {
//to access the index you could then do:
const idx = Number(key.split('[')[1].split(']')[0])
const sub_key = key.split('.')[1]
//not here that i don't verify if the index exists
if (!qualifications[idx]) qualifications[idx] = {}
qualifications[idx][sub_key] = my_object[key]
})