有如下表格结构
create table T_CASE
(
contractid VARCHAR2(20), --合同号
applyervocation VARCHAR2(100),--申请人职业
contractamount NUMBER(10,4),--申请合同金额
applyerage NUMBER(5), --申请人年龄
historyoverduedays NUMBER(5) --最大历史逾期天数
)
根据申请人职业,金额,年龄 分组,求每个分组里的最大逾期天数超过30天和未超过30天的数据
------解决方案--------------------
select applyervocation,contractamount,applyerage,max(historyoverduedays) from T_CASE你试试看
group by applyervocation,contractamount,applyerage
having max(historyoverduedays>30
------解决方案--------------------
select applyervocation,contractamount,applyerage,
sum(case when historyoverduedays>30 then 1 end) "逾期超过超过30天",
sum(case when historyoverduedays<=30 then 1 end) "逾期未超过超过30天"
from T_CASE
group by applyervocation,contractamount,applyerage